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x^2+0.25x+1.x(0)=2.x(0)=0
We move all terms to the left:
x^2+0.25x+1.x(0)-(2.x(0))=0
We add all the numbers together, and all the variables
x^2+0.25x+1.x0-(+2.x)=0
We add all the numbers together, and all the variables
x^2+1.25x-(+2.x)=0
We get rid of parentheses
x^2+1.25x-2.x=0
We add all the numbers together, and all the variables
x^2-0.75x=0
a = 1; b = -0.75; c = 0;
Δ = b2-4ac
Δ = -0.752-4·1·0
Δ = 0.5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.75)-\sqrt{0.5625}}{2*1}=\frac{0.75-\sqrt{0.5625}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.75)+\sqrt{0.5625}}{2*1}=\frac{0.75+\sqrt{0.5625}}{2} $
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